Special characters inside [ ]
become
regular characters. This means that they don't
need to be escaped with a backslash.
Example
In this example, the search pattern looks like
this: any letter 'a'
, 'b'
,
'c'
, or a dot is between x
's:
let str = 'xax xbx xcx xdx x.x x@x';
let res = str.replace(/x[abc.]x/g, '!');
As a result, the following will be written to the variable:
'! ! ! xdx ! x@x'
Example
In this example, the search pattern looks
like this: any small Latin letter or
dot is between x
's:
let str = 'xax xbx xcx x@x';
let res = str.replace(/x[a-z.]x/g, '!');
As a result, the following will be written to the variable:
'! ! ! x@x'
Practical tasks
Given a string:
let str = 'aba aea aca aza axa a.a a+a a*a';
Write a regex that will find the 'a.a'
,
'a+a'
, 'a*a'
strings without
affecting the others.
Given a string:
let str = 'xaz x.z x3z x@z x$z xrz';
Write a regex that matches strings with the
pattern: letter 'x'
, then NOT a
dot, NOT an AT sign, and NOT a dollar
symbol, and then letter 'z'
.